In recent years, with the advent of concepts such as cloud computing and big data, distributed systems have gained popularity and relevance.

One such type of system, distributed caches that power many high-traffic dynamic websites and web applications, typically consist of a particular case of distributed hashing. These take advantage of an algorithm known as consistent hashing.

What is consistent hashing? What’s the motivation behind it, and why should you care?

In this article, I’ll first review the general concept of hashing and its purpose, followed by a description of distributed hashing and the problems it entails. In turn, that will lead us to our title subject.

**What Is Hashing?**

What is “hashing” all about? Merriam-Webster defines the noun hash as “chopped meat mixed with potatoes and browned,” and the verb as “to chop (as meat and potatoes) into small pieces.” So, culinary details aside, hash roughly means “chop and mix”—and that’s precisely where the technical term comes from.

A hash function is a function that maps one piece of data—typically describing some kind of object, often of arbitrary size—to another piece of data, typically an integer, known as hash code, or simply hash.

For instance, some hash function designed to hash strings, with an output range of 0 .. 100, may map the string Hello to, say, the number 57, Hasta la vista, baby to the number 33, and any other possible string to some number within that range. Since there are way more possible inputs than outputs, any given number will have many different strings mapped to it, a phenomenon known as

*collision*. Good hash functions should somehow “chop and mix” (hence the term) the input data in such a way that the outputs for different input values are spread as evenly as possible over the output range.
Hash functions have many uses and for each one, different properties may be desired. There is a type of hash function known as

*cryptographic hash functions*, which must meet a restrictive set of properties and are used for security purposes—including applications such as password protection, integrity checking and fingerprinting of messages, and data corruption detection, among others, but those are outside the scope of this article.
Non-cryptographic hash functions have several uses as well, the most common being their use in

*hash tables*, which is the one that concerns us and which we’ll explore in more detail.**Introducing Hash Tables (Hash Maps)**

Imagine we needed to keep a list of all the members of some club while being able to search for any specific member. We could handle it by keeping the list in an array (or linked list) and, to perform a search, iterate the elements until we find the desired one (we might be searching based on their name, for instance). In the worst case, that would mean checking all members (if the one we’re searching for is last, or not present at all), or half of them on average. In complexity theory terms, the search would then have complexity O(n), and it would be reasonably fast for a small list, but it would get slower and slower in direct proportion to the number of members.

How could that be improved? Let’s suppose all these club members had a member ID, which happened to be a sequential number reflecting the order in which they joined the club.

Assuming that searching by ID were acceptable, we could place all members in an array, with their indexes matching their IDs (for example, a member with ID=10 would be at the index 10 in the array). This would allow us to access each member directly, with no search at all. That would be very efficient, in fact, as efficient as it can possibly be, corresponding to the lowest complexity possible, O(1), also known as constant time.

But, admittedly, our club member ID scenario is somewhat contrived. What if IDs were big, non-sequential or random numbers? Or, if searching by ID were not acceptable, and we needed to search by name (or some other field) instead? It would certainly be useful to keep our fast direct access (or something close) while at the same time being able to handle arbitrary datasets and less restrictive search criteria.

Here’s where hash functions come to the rescue. A suitable hash function can be used to map an arbitrary piece of data to an integer, which will play a similar role to that of our club member ID, albeit with a few important differences.

First, a good hash function generally has a wide output range (typically, the whole range of a 32 or 64-bit integer), so building an array for all possible indices would be either impractical or plain impossible, and a colossal waste of memory. To overcome that, we can have a reasonably sized array (say, just twice the number of elements we expect to store) and perform a

*modulo*operation on the hash to get the array index. So, the index would be index = hash(object) mod N, where N is the size of the array.
Second, object hashes will not be unique (unless we’re working with a fixed dataset and a custom-built perfect hash function, but we won’t discuss that here). There will be

*collisions*(further increased by the modulo operation), and therefore a simple direct index access won’t work. There are several ways to handle this, but a typical one is to attach a list, commonly known as a bucket, to each array index to hold all the objects sharing a given index.
So, we have an array of size N, with each entry pointing to an object bucket. To add a new object, we need to calculate its hash modulo N, and check the bucket at the resulting index, adding the object if it’s not already there. To search for an object, we do the same, just looking into the bucket to check if the object is there. Such a structure is called a

*hash table*, and although the searches within buckets are linear, a properly sized hash table should have a reasonably small number of objects per bucket, resulting in*almost*constant time access (an average complexity of O(N/k), where k is the number of buckets).
With complex objects, the hash function is typically not applied to the whole object, but to a key instead. In our club member example, each object might contain several fields (like name, age, address, email, phone), but we could pick, say, the email to act as the key so that the hash function would be applied to the email only. In fact, the key need not be part of the object; it is common to store key/value pairs, where the key is usually a relatively short string, and the value can be an arbitrary piece of data. In such cases, the hash table or hash map is used as a

*dictionary*, and that’s the way some high-level languages implement objects or associative arrays.**Scaling Out: Distributed Hashing**

Now that we have discussed hashing, we’re ready to look into

*distributed hashing*.
In some situations, it may be necessary or desirable to split a hash table into several parts, hosted by different servers. One of the main motivations for this is to bypass the memory limitations of using a single computer, allowing for the construction of arbitrarily large hash tables (given enough servers).

In such a scenario, the objects (and their keys) are

*distributed*among several servers, hence the name.
Such setups consist of a pool of caching servers that host many key/value pairs and are used to provide fast access to data originally stored (or computed) elsewhere. For example, to reduce the load on a database server and at the same time improve performance, an application can be designed to first fetch data from the cache servers, and only if it’s not present there—a situation known as

*cache miss*—resort to the database, running the relevant query and caching the results with an appropriate key, so that it can be found next time it’s needed.
Now, how does distribution take place? What criteria are used to determine which keys to host in which servers?

The simplest way is to take the hash modulo of the number of servers. That is, sserver = hash(key) mod N, where N is the size of the pool. To store or retrieve a key, the client first computes the hash, applies a modulo N operation, and uses the resulting index to contact the appropriate server (probably by using a lookup table of IP addresses). Note that the hash function used for key distribution must be the same one across all clients, but it need not be the same one used internally by the caching servers.

Let’s see an example. Say we have three servers, A, B and C, and we have some string keys with their hashes:

KEY | HASH | HASH mod 3 |
---|---|---|

"john" | 1633428562 | 2 |

"bill" | 7594634739 | 0 |

"jane" | 5000799124 | 1 |

"steve" | 9787173343 | 0 |

"kate" | 3421657995 | 2 |

A client wants to retrieve the value for key john. Its hash modulo 3 is 2, so it must contact server C. The key is not found there, so the client fetches the data from the source and adds it. The pool looks like this:

A | B | C |
---|---|---|

"john" |

Next another client (or the same one) wants to retrieve the value for key bill. Its hash modulo 3 is 0, so it must contact server A. The key is not found there, so the client fetches the data from the source and adds it. The pool looks like this now:

A | B | C |
---|---|---|

"bill" | "john" |

After the remaining keys are added, the pool looks like this:

A | B | C |
---|---|---|

"bill" | "jane" | "john" |

"steve" | "kate" |

**The Rehashing Problem**

This distribution scheme is simple, intuitive, and works fine. That is, until the number of servers changes. What happens if one of the servers crashes or becomes unavailable? Keys need to be redistributed to account for the missing server, of course. The same applies if one or more new servers are added to the pool;keys need to be redistributed to include the new servers. This is true for any distribution scheme, but the problem with our simple modulo distribution is that when the number of servers changes, most hashes modulo N will change, so most keys will need to be moved to a different server. So, even if a single server is removed or added, all keys will likely need to be rehashed into a different server.

From our previous example, if we removed server C, we’d have to rehash all the keys using hash modulo 2 instead of hash modulo 3, and the new locations for the keys would become:

KEY | HASH | HASH mod 2 |
---|---|---|

"john" | 1633428562 | 0 |

"bill" | 7594634739 | 1 |

"jane" | 5000799124 | 0 |

"steve" | 9787173343 | 1 |

"kate" | 3421657995 | 1 |

A | B |
---|---|

"john" | "bill" |

"jane" | "steve" |

"kate" |

Note that all key locations changed, not only the ones from server C.

In the typical use case we mentioned before (caching), this would mean that, all of a sudden, the keys won’t be found because they won’t yet be present at their new location.

So, most queries will result in misses, and the original data will likely need retrieving again from the source to be rehashed, thus placing a heavy load on the origin server(s) (typically a database). This may very well degrade performance severely and possibly crash the origin servers.

**The Solution: Consistent Hashing**

So, how can this problem be solved? We need a distribution scheme that does not depend directly on the number of servers, so that, when adding or removing servers, the number of keys that need to be relocated is minimized. One such scheme—a clever, yet surprisingly simple one—is called

*consistent hashing*, and was first described by Karger et al. at MIT in an academic paper from 1997 (according to Wikipedia).
Consistent Hashing is a distributed hashing scheme that operates independently of the number of servers or objects in a distributed

*hash table*by assigning them a position on an abstract circle, or*hash ring*. This allows servers and objects to scale without affecting the overall system.
Imagine we mapped the hash output range onto the edge of a circle. That means that the minimum possible hash value, zero, would correspond to an angle of zero, the maximum possible value (some big integer we’ll call INT_MAX) would correspond to an angle of 2𝝅 radians (or 360 degrees), and all other hash values would linearly fit somewhere in between. So, we could take a key, compute its hash, and find out where it lies on the circle’s edge. Assuming an INT_MAX of 1010 (for example’s sake), the keys from our previous example would look like this:

KEY | HASH | ANGLE (DEG) |
---|---|---|

"john" | 1633428562 | 58.8 |

"bill" | 7594634739 | 273.4 |

"jane" | 5000799124 | 180 |

"steve" | 9787173343 | 352.3 |

"kate" | 3421657995 | 123.2 |

Now imagine we also placed the servers on the edge of the circle, by pseudo-randomly assigning them angles too. This should be done in a repeatable way (or at least in such a way that all clients agree on the servers’ angles). A convenient way of doing this is by hashing the server name (or IP address, or some ID)—as we’d do with any other key—to come up with its angle.

In our example, things might look like this:

KEY | HASH | ANGLE (DEG) |
---|---|---|

"john" | 1633428562 | 58.8 |

"bill" | 7594634739 | 273.4 |

"jane" | 5000799124 | 180 |

"steve" | 9787173343 | 352.3 |

"kate" | 3421657995 | 123.2 |

"A" | 5572014558 | 200.6 |

"B" | 8077113362 | 290.8 |

"C" | 2269549488 | 81.7 |

Since we have the keys for both the objects and the servers on the same circle, we may define a simple rule to associate the former with the latter: Each object key will belong in the server whose key is closest, in a counterclockwise direction (or clockwise, depending on the conventions used). In other words, to find out which server to ask for a given key, we need to locate the key on the circle and move in the ascending angle direction until we find a server.

In our example:

KEY | HASH | ANGLE (DEG) |
---|---|---|

"john" | 1633428562 | 58.7 |

"C" | 2269549488 | 81.7 |

"kate" | 3421657995 | 123.1 |

"jane" | 5000799124 | 180 |

"A" | 5572014557 | 200.5 |

"bill" | 7594634739 | 273.4 |

"B" | 8077113361 | 290.7 |

"steve" | 787173343 | 352.3 |

KEY | HASH | ANGLE (DEG) | LABEL | SERVER |
---|---|---|---|---|

"john" | 1632929716 | 58.7 | "C" | C |

"kate" | 3421831276 | 123.1 | "A" | A |

"jane" | 5000648311 | 180 | "A" | A |

"bill" | 7594873884 | 273.4 | "B" | B |

"steve" | 9786437450 | 352.3 | "C" | C |

From a programming perspective, what we would do is keep a sorted list of server values (which could be angles or numbers in any real interval), and walk this list (or use a binary search) to find the first server with a value greater than, or equal to, that of the desired key. If no such value is found, we need to wrap around, taking the first one from the list.

To ensure object keys are evenly distributed among servers, we need to apply a simple trick: To assign not one, but many labels (angles) to each server. So instead of having labels A, B and C, we could have, say, A0 .. A9, B0 .. B9 and C0 .. C9, all interspersed along the circle. The factor by which to increase the number of labels (server keys), known as

*weight*, depends on the situation (and may even be different for each server) to adjust the probability of keys ending up on each. For example, if server B were twice as powerful as the rest, it could be assigned twice as many labels, and as a result, it would end up holding twice as many objects (on average).
For our example we’ll assume all three servers have an equal weight of 10 (this works well for three servers, for 10 to 50 servers, a weight in the range 100 to 500 would work better, and bigger pools may need even higher weights):

KEY | HASH | ANGLE (DEG) |
---|---|---|

"C6" | 408965526 | 14.7 |

"A1" | 473914830 | 17 |

"A2" | 548798874 | 19.7 |

"A3" | 1466730567 | 52.8 |

"C4" | 1493080938 | 53.7 |

"john" | 1633428562 | 58.7 |

"B2" | 1808009038 | 65 |

"C0" | 1982701318 | 71.3 |

"B3" | 2058758486 | 74.1 |

"A7" | 2162578920 | 77.8 |

"B4" | 2660265921 | 95.7 |

"C9" | 3359725419 | 120.9 |

"kate" | 3421657995 | 123.1 |

"A5" | 3434972143 | 123.6 |

"C1" | 3672205973 | 132.1 |

"C8" | 3750588567 | 135 |

"B0" | 4049028775 | 145.7 |

"B8" | 4755525684 | 171.1 |

"A9" | 4769549830 | 171.7 |

"jane" | 5000799124 | 180 |

"C7" | 5014097839 | 180.5 |

"B1" | 5444659173 | 196 |

"A6" | 6210502707 | 223.5 |

"A0" | 6511384141 | 234.4 |

"B9" | 7292819872 | 262.5 |

"C3" | 7330467663 | 263.8 |

"C5" | 7502566333 | 270 |

"bill" | 7594634739 | 273.4 |

"A4" | 8047401090 | 289.7 |

"C2" | 8605012288 | 309.7 |

"A8" | 8997397092 | 323.9 |

"B7" | 9038880553 | 325.3 |

"B5" | 9368225254 | 337.2 |

"B6" | 9379713761 | 337.6 |

"steve" | 9787173343 | 352.3 |

KEY | HASH | ANGLE (DEG) | LABEL | SERVER |
---|---|---|---|---|

"john" | 1632929716 | 58.7 | "B2" | B |

"kate" | 3421831276 | 123.1 | "A5" | A |

"jane" | 5000648311 | 180 | "C7" | C |

"bill" | 7594873884 | 273.4 | "A4" | A |

"steve" | 9786437450 | 352.3 | "C6" | C |

So, what’s the benefit of all this circle approach? Imagine server C is removed. To account for this, we must remove labels C0 .. C9 from the circle. This results in the object keys formerly adjacent to the deleted labels now being randomly labeled Ax and Bx, reassigning them to servers A and B.

But what happens with the other object keys, the ones that originally belonged in A and B? Nothing! That’s the beauty of it: The absence of Cx labels does not affect those keys in any way. So, removing a server results in its object keys being randomly reassigned to the rest of the servers, leaving all other keys untouched:

KEY | HASH | ANGLE (DEG) |
---|---|---|

"A1" | 473914830 | 17 |

"A2" | 548798874 | 19.7 |

"A3" | 1466730567 | 52.8 |

"john" | 1633428562 | 58.7 |

"B2" | 1808009038 | 65 |

"B3" | 2058758486 | 74.1 |

"A7" | 2162578920 | 77.8 |

"B4" | 2660265921 | 95.7 |

"kate" | 3421657995 | 123.1 |

"A5" | 3434972143 | 123.6 |

"B0" | 4049028775 | 145.7 |

"B8" | 4755525684 | 171.1 |

"A9" | 4769549830 | 171.7 |

"jane" | 5000799124 | 180 |

"B1" | 5444659173 | 196 |

"A6" | 6210502707 | 223.5 |

"A0" | 6511384141 | 234.4 |

"B9" | 7292819872 | 262.5 |

"bill" | 7594634739 | 273.4 |

"A4" | 8047401090 | 289.7 |

"A8" | 8997397092 | 323.9 |

"B7" | 9038880553 | 325.3 |

"B5" | 9368225254 | 337.2 |

"B6" | 9379713761 | 337.6 |

"steve" | 9787173343 | 352.3 |

KEY | HASH | ANGLE (DEG) | LABEL | SERVER |
---|---|---|---|---|

"john" | 1632929716 | 58.7 | "B2" | B |

"kate" | 3421831276 | 123.1 | "A5" | A |

"jane" | 5000648311 | 180 | "B1" | B |

"bill" | 7594873884 | 273.4 | "A4" | A |

"steve" | 9786437450 | 352.3 | "A1" | A |

Something similar happens if, instead of removing a server, we add one. If we wanted to add server D to our example (say, as a replacement for C), we would need to add labels D0 .. D9. The result would be that roughly one-third of the existing keys (all belonging to A or B) would be reassigned to D, and, again, the rest would stay the same:

KEY | HASH | ANGLE (DEG) |
---|---|---|

"D2" | 439890723 | 15.8 |

"A1" | 473914830 | 17 |

"A2" | 548798874 | 19.7 |

"D8" | 796709216 | 28.6 |

"D1" | 1008580939 | 36.3 |

"A3" | 1466730567 | 52.8 |

"D5" | 1587548309 | 57.1 |

"john" | 1633428562 | 58.7 |

"B2" | 1808009038 | 65 |

"B3" | 2058758486 | 74.1 |

"A7" | 2162578920 | 77.8 |

"B4" | 2660265921 | 95.7 |

"D4" | 2909395217 | 104.7 |

"kate" | 3421657995 | 123.1 |

"A5" | 3434972143 | 123.6 |

"D7" | 3567129743 | 128.4 |

"B0" | 4049028775 | 145.7 |

"B8" | 4755525684 | 171.1 |

"A9" | 4769549830 | 171.7 |

"jane" | 5000799124 | 180 |

"B1" | 5444659173 | 196 |

"D6" | 5703092354 | 205.3 |

"A6" | 6210502707 | 223.5 |

"A0" | 6511384141 | 234.4 |

"B9" | 7292819872 | 262.5 |

"bill" | 7594634739 | 273.4 |

"A4" | 8047401090 | 289.7 |

"D0" | 8272587142 | 297.8 |

"A8" | 8997397092 | 323.9 |

"B7" | 9038880553 | 325.3 |

"D3" | 9048608874 | 325.7 |

"D9" | 9314459653 | 335.3 |

"B5" | 9368225254 | 337.2 |

"B6" | 9379713761 | 337.6 |

"steve" | 9787173343 | 352.3 |

KEY | HASH | ANGLE (DEG) | LABEL | SERVER |
---|---|---|---|---|

"john" | 1632929716 | 58.7 | "B2" | B |

"kate" | 3421831276 | 123.1 | "A5" | A |

"jane" | 5000648311 | 180 | "B1" | B |

"bill" | 7594873884 | 273.4 | "A4" | A |

"steve" | 9786437450 | 352.3 | "D2" | D |

This is how consistent hashing solves the rehashing problem.

In general, only k/N keys need to be remapped when k is the number of keys and N is the number of servers (more specifically, the maximum of the initial and final number of servers).

**What Next?**

We observed that when using distributed caching to optimize performance, it may happen that the number of caching servers changes (reasons for this may be a server crashing, or the need to add or remove a server to increase or decrease overall capacity). By using consistent hashing to distribute keys between the servers, we can rest assured that should that happen, the number of keys being rehashed—and therefore, the impact on origin servers—will be minimized, preventing potential downtime or performance issues.

There are clients for several systems, such as Memcached and Redis, that include support for consistent hashing out of the box.

Alternatively, you can implement the algorithm yourself, in your language of choice, and that should be relatively easy once the concept is understood.

If data science interests you, Toptal has some of the best articles on the subject at the blog

**About the author**

JUAN PABLO CARZOLIO

Source: toptal.com